Math 20A   Updates     Booklets

Shannon Sookochoff's and Jim Reed's Applied Correspondence Course Updates

Argyll Centre, Edmonton, Alberta, Canada

2010/2011 Semester 1/2

Ms. Shannon Sookochoff is your teacher. (Until April, 2011, she is team teaching your course with Mr. Jim Reed.) Please see the course information posted at shannon.sookochoff.wordpress.ca.
You are asked to contact Shannon as soon as possible. Please use the contact information provided at shannon.sookochoff.wordpress.ca.

Complete the Project Booklets for Modules 1 and 5 only. Summer students omit Project Booklet for Modules 5 as well.

Mr. Reed's Math 20 Applied Website

LearnAlberta Online Lessons - Alberta students may get the userID/password from their instructor.

Formula Sheet - may be used with all course assignments and final exam. Print a copy and use regularly. The digital copy has links to formula notes that may help make the printed copy even more useful.

TI-83 Calculator

Complete the Project Booklets for Modules 1 and 5 only. Summer students omit Project Booklet for Modules 5 as well.

Module 1 - Graphs

Assignment Booklet

  • page 10, question 9: Ä means "not A". Ä is the
  • outside of circle A.

Project Booklet

  • Some students have trouble finding relevant articles. If you need an article for Part A, B or C, check the following:
Part A - page 1 http://www.statcan.ca/english/freepub/11-010-XIB/01008/feature.htm - there are several graphs - pick one to base your answers for questions 1 and 2.
Part B - page 2 http://www.statcan.ca/english/freepub/11-010-XIB/01008/feature.htm - the chart is at the end of the article. Don't try to graph all of the data. Pick one pair (e.g. Men vs Women) for your graph. Consider a bar graph so that I can see the differences that are revealed in the data. Include data for at least 3 columns for your graph.
Part C - page 4 Check graph in 9. Patient satisfaction: http://www.hc-sc.gc.ca/hcs-sss/pubs/system-regime/2002-fed-comp-indicat/2002-health-sante7-eng.php

 

Project Booklet, page 2, #2

  • If you are having trouble finding an article, use:

Project Booklet, page 3, #3

  • Draw and complete the following charts in your project booklet.
Use 1960 as the starting point for this chart. You will need to create an exponential equation based on the 1960 data given in the Applied Math 11 text on page 84.   Use 1970 or 1980 ori 1990 as the starting point for this chart.
Year
n
Prediction (billions)
Year
n
Prediction (billions)
2000
2000-1960 = 40
 
2000
 
 
2010
 
 
2010
 
 
2020
 
 
2020
 
 
2100
 
 
2100
 
 

Project Booklet, page 4, Omit #5,

Project Booklet, page 5, Complete 6a)

Project Booklet, page 6, Draw and complete the following chart for 6b):

Use 1990 as the starting point for this chart. You will need to use the exponential equation given on the previous page of the projecct booklet..
Year
n
Prediction (billions)
2000
 
 
2010
 
 
2100
 
 

Project Booklet, page 6, 6c. Modify the chart as show below, then complete.

x
Year
Predicted Population Based on 1950 Figures (in billions)
M = 8 billion
M = 18 billioin
M = 28 billion
Formula provided in chart on page 6 of Module 1 Project Booklet.
Formula provided in chart on page 6 of Module 1 Project Booklet.
Formula provided in chart on page 6 of Module 1 Project Booklet.
 
2000
 
 
  
 
2010
 
 
 
 
2020
 
 
 
 
2100
 
 
 

 

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit. You can check your system and install required plugins at: http://www.learnalberta.ca/BrowserHawk/BrowserHawkDetection.aspx

Module 2 - Non-Linear Functions

  • Omit Project Booklet for Module 2.
  • Project Booklet - page 4: You will not have the WORLDPOP program. Complete question 6 - omit question 5.

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

 

Module 3 - Linear Systems - notes to look over this resource before starting the assignment booklets

Project Booklet - omit pages 6-11 (questions 4-5).

  • Omit Project Booklet for Module 3.

Assignment Booklet

page 12, #14 a) b)

Background Info:

First review vocabulary: 3x + 4y = 6

  • variables: x and y are variables
  • coefficient: number in front of a variable: 3 and 4 are coefficents
  • constant: number only (not attached to a varialble): 6 is a constant


For a system of two equations, the solution(s) can be one point (intersecting line), no points ( parallel lines), or all points ('overlapping' lines).

Understand that parallel lines and 'overlapping lines' have the same slope.

Start with an equation:

3x + 4y = 6

  • An equation that will form a system of lines with one intersection point will have a different slope than the intial equation.

    2(3x) + 1(4y) = 6

    New equation: 6x + 4y = 6

    Notice only the variable terms are multiplied by a different factor. The corresponding ratios of the coefficients are different,

  • An equation forming a system of parallel lines (no solution) with 2x + 3y = 6 is:

2 x [2x + 3y] = 6

New equation: 4x + 6y = 6

Notice only the variable terms are multiplied by the same factor. The corresponding ratios of the coefficients are the same, but the corresponding ratio of the constants is different.

2x + 3y = 6
4x + 6y = 6

  • An equation that will form a system of 'Overlapping' lines is:
    2 x [3x + 4y = 6] - notice all the terms are multiplied by the same factor

6x + 8y =12

Notice: The corresponding ratios of the coefficients and the constants are the same for a system of equations the creates 'overlapping lines'. In this case the ratio is 2 because the number we multiplied the first equation by was 2.
3x + 4y = 6
6x +8y =12


------------------------------------------------------

Solving the Question:

Now look at 14b:

The following is an example of a system of equations with no solutions
3x + 4y = 6
6x + 8y = 6
Use the model provided in the first part of this message to make up your own system

Now look at 14a - analyze the system

3x + 4y = 6
6x + 8y = 6
How do the corresponding ratios of the coefficients compare to the ratio of the constants? The answer to this is the answer to 14a)

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

Module 4 - Linear Programming

  • Omit Project Booklet for Module 4.

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

Module 5 - Finance.

Error in the coiled booklet, page 40.

  • Starts ok: "To access the financial features, press the following:"
  • BUT directions should be: [ APPS ] ---------> 1: Finance ---------> 1: TVM Solver

    Please write this change into your coiled booklet.

Assignment Booklet

  • Question 11a and 11b - The question refers to a spreadsheet created. The format for this spreadsheet is shown in Addison-Wesley, Applied Math 11 on pages 264-265.
  • Question 13 - The question refers to a chart in Addison-Wesley, Applied Math 11 on page 271. Draw the following table, then fill it in. The first cell is completed for you.
Expense Category
Amount ($)
Housing and Utilities

$(525+55+40+50+

= $670

Food and Clothing
 
Health and Personal Care
 
Transportation
 
Recreation and Education
 
Savings
 
Miscellaneous
 

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

Module 6 - Circles - notes - look over this resource before starting the assignment booklet

Assignment Booklet Module 6

Module Assignment

page 1, Q1 - If you know the lengths of 2 sides of a right triangle, you can calculate the third using the Pythagorean Theorem. Click [Check/Explain] to see a sample solution and calculator keystrokes. Click [New Problem], and [Check/Explain] several more times until you understand the steps needed to solve for the longest side (hypotenuese). This is not the side you need to find in Q1.

Click [Next Type] to see a sample solution and calculator keystrokes for question that matches your picture - you may have to rotate your picture to match the activity below. Use these steps to solve Q3 in the assignment booklet.

page 2, Q2 - Calculate the length of the radius first. Remember: If you know the lengths of 2 sides of a right triangle, you can calculate the third using the Pythagorean Theorem. You may have to draw an additional line to solve this question. If that additional line is a radius, you have already calculated that length.

page 2, Q3

Perpendicular Bisector of a Chord Properties

  1. If you have a line through the centre of the circle which is perpendicular to a given chord, then the line bisects the chord (cuts the chord into two equal segments)..
  2. If you have a line through the centre of the circle which bisects the chord (cuts the chord into two equal segments), then the line is perpendicular to the chord.
  3. If you have a line which is a perpendicular bisector of a given chord (cuts the chord into two equal segments and intersects the chord at a right angle), then that line will pass through the centre of the circle.

If you have any two of the above statements, then the third is true.

Linked Source - Ron Blond

page 3, Q3a

The tangent segments to a circle from an external point are equal.

Graphic

Linked Source - Ron Blond

 

A tangent to a circle is perpendicular to the radius at the point of tangency.

Graphic

Linked Source - Ron Blond

Use the Pythagorean Theorem to calculate the missing side lengths.

page 3, Q3b

The angle between a tangent and a chord is equal to the inscribed angle on the opposite side of the chord.

Linked Source - Ron Blond

 

The sum of angles that form a line is 180o.

page 4, Q4 - Try this on on your own.

page 4, Q5a

The measure of the central angle is twice the measure of an inscribed angle, subtended by the same arc.

Linked Source - Ron Blond

 

page 4, Q5b - Try this one on your own.

page 5, Q6a

Inscribed angles subtended by the same arc of a circle are equal.

Linked Source - Ron Blond

page 5, Q6b

Triangle Types:
Characteristics

Scalene

no two sides are congruent

Isosceles two sides are congruent. Note: The sides opposite the equal angle are also equal.
Equilateral all three sides are congruent. Note: The sides opposite the equal angle are also equal.

Click the applet once to activate: Use the applet to create an isosceles triangle (exactly two sides are inscribed in the same circle. Note that the angles opposite the equal sides are also equal.

 

Any angle inscribed in a semicircle is always a right angle.

For the interactive on the right, move vertices to form an angle inscribed in a semicircle.

Graphic

Linked Source - Ron Blond

page 6, Q7

Set the number of sides to 30. Notice how close the regular polygon is to a circle. Use the circumference formula to calculate a close appoximation to the perimeter of the polyon. With this hint you will likely be able to finish this question.

 

page 7, Q8

The opposite angles of a cyclic quadrilateral are supplementary (total 180o). Therefore the angles in a cyclic quadrilateral total 360o.

 

Linked Source - Ron Blond

page 7, Q9

Angles that form a line (total 180°) are supplementary angles.

The opposite angles of a cyclic quadrilateral are supplementary (total 180o). Therefore the angles in a cyclic quadrilateral total 360o.

 

Linked Source - Ron Blond

The measure of the central angle is twice the measure of an inscribed angle, subtended by the same arc.

Linked Source - Ron Blond

 

 

page 8, Q10

The sum of the interior angles in a regular polgyon is equal to 180(n-2), where n is the number of sides of the polygon. Measure of Each Interior Angle is equal to [180(n-2)]/n.

page 9, Q11 - Try this one on your own.

page 10, Q12 - Try this one on your own.

page 11, Q13 - Try this one on your own.

  • Omit Project Booklet for Module 6.

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

  • No multimedia segments available.

Module 7 - Measurement

  • Omit Project Booklet for Module 7.

Companion CD included in coiled booklet for Module 1 includes the following resources for this unit.

  • Measuring - not available at this time
  • Precision: Floppy disk - not available at this time
  • Percentage Error - not available at this time
  • Machinist - not available at this time
  • Precision and Accuracy - not available at this time

 

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