Shannon Sookochoff's and Jim Reed's Applied Correspondence Course Updates
Argyll Centre,
Edmonton, Alberta, Canada
2010/2011 Semester 1/2
Ms. Shannon Sookochoff is your teacher. (Until April, 2011, she is team teaching your course with Mr. Jim Reed.) Please see the course information posted at shannon.sookochoff.wordpress.ca.
You are asked to contact Shannon as soon as possible. Please use the contact information provided at shannon.sookochoff.wordpress.ca.
Complete the Project Booklets for Modules 1 and 5 only. Summer students
omit Project Booklet for Modules 5 as well.
Formula Sheet - may be
used with all course assignments and final exam. Print a copy and use
regularly. The digital copy has links to formula notes that may help
make the printed copy even more useful.
http://www.statcan.ca/english/freepub/11-010-XIB/01008/feature.htm -
the chart is at the end of the article. Don't try to graph all of
the data. Pick one pair (e.g. Men vs Women) for your graph. Consider
a bar graph so that I can see the differences that are revealed in
the data. Include data for at least 3 columns for your graph.
If you are having trouble finding an article, use:
Project Booklet, page 3, #3
Draw and complete the following charts in your project booklet.
Use 1960 as the starting point for this chart. You
will need to create an exponential equation based on the 1960 data
given in the Applied Math 11 text on page 84.
Use 1970 or 1980 ori 1990 as the starting point for
this chart.
Year
n
Prediction (billions)
Year
n
Prediction (billions)
2000
2000-1960 = 40
2000
2010
2010
2020
2020
2100
2100
Project Booklet, page 4, Omit #5,
Project Booklet, page 5, Complete 6a)
Project Booklet, page 6, Draw and complete the following chart for 6b):
Use 1990 as the starting point for this chart. You
will need to use the exponential equation given on the previous page
of the projecct booklet..
Year
n
Prediction (billions)
2000
2010
2100
Project Booklet, page 6, 6c. Modify the chart as show below, then complete.
x
Year
Predicted Population Based on 1950 Figures (in billions)
M = 8 billion
M = 18 billioin
M = 28 billion
Formula provided in chart on page 6 of Module 1
Project Booklet.
Formula
provided in chart on page 6 of Module 1 Project Booklet.
Formula
provided in chart on page 6 of Module 1 Project Booklet.
coefficient: number in front of a variable:
3 and 4 are coefficents
constant: number only (not attached to a varialble):
6 is a constant
For a system of two equations, the solution(s) can be one point (intersecting
line), no points ( parallel lines), or all points ('overlapping' lines).
Understand that parallel lines and 'overlapping lines' have the same slope.
Start with an equation:
3x + 4y = 6
An equation that will form a system of lines with one intersection
point will have a different slope than the intial equation.
2(3x) + 1(4y) = 6
New equation: 6x + 4y = 6
Notice only the variable terms are multiplied by a different factor.
The corresponding ratios of the coefficients are different,
An equation forming a system of parallel lines (no solution) with 2x +
3y = 6 is:
2 x [2x + 3y] = 6
New equation: 4x + 6y = 6
Notice only the variable terms are multiplied by the same factor. The
corresponding ratios of the coefficients are the same, but the corresponding
ratio of the constants is different.
2x + 3y = 6
4x + 6y = 6
An equation that will form a system of 'Overlapping' lines is:
2 x [3x + 4y = 6] - notice all the terms are multiplied by the same factor
6x + 8y =12
Notice: The corresponding ratios of the coefficients and the constants
are the same for a system of equations the creates 'overlapping lines'.
In this case the ratio is 2 because the number we multiplied the first
equation by was 2.
3x + 4y = 6
6x +8y =12
The following is an example of a system of equations with no solutions
3x + 4y = 6
6x + 8y = 6
Use the model provided in the first part of this message to make up your
own system
Now look at 14a - analyze the system
3x + 4y = 6
6x + 8y = 6
How do the corresponding ratios of the coefficients compare to the ratio
of the constants? The answer to this is the answer to 14a)
Companion CD included in coiled booklet for Module 1 includes the following
resources for this unit.
Starts ok: "To access the financial features, press the following:"
BUT directions should be: [ APPS ] ---------> 1:
Finance ---------> 1: TVM Solver
Please write this change into your coiled booklet.
Assignment Booklet
Question 11a and 11b - The question refers to a spreadsheet created.
The format for this spreadsheet is shown in Addison-Wesley, Applied
Math 11 on pages 264-265.
Question 13 - The question refers to a chart in Addison-Wesley, Applied
Math 11 on page 271. Draw the following table, then fill it in. The
first cell is completed for you.
Expense Category
Amount ($)
Housing and Utilities
$(525+55+40+50+
= $670
Food and Clothing
Health and Personal Care
Transportation
Recreation and Education
Savings
Miscellaneous
Companion CD included in coiled booklet for Module 1 includes
the following resources for this unit.
page 1, Q1 - If you know the lengths of 2 sides of a
right triangle, you can calculate the third using the Pythagorean Theorem.
Click [Check/Explain] to see a sample solution and calculator
keystrokes.
Click [New Problem],
and
[Check/Explain]
several more times until you understand the steps needed to solve for
the longest side (hypotenuese). This is not the side
you need to find in Q1.
Click [Next Type] to see a sample solution and calculator
keystrokes for question that matches your picture - you may have to
rotate your picture to match the activity below. Use these steps to solve
Q3 in the assignment booklet.
page 2, Q2 - Calculate the length of the radius first. Remember: If
you know the lengths of 2 sides of a right triangle, you can calculate
the third
using the
Pythagorean Theorem. You may have to draw an additional line to solve
this question. If that additional line is a radius, you have already
calculated that length.
page 2, Q3
Perpendicular Bisector of a Chord Properties
If you have a line through the centre of the circle which is
perpendicular to a given chord, then the line bisects the chord
(cuts the chord into two equal segments)..
If you have a line through the centre of the circle which bisects
the chord (cuts the chord into two equal segments), then the
line is perpendicular to the chord.
If you have a line which is a perpendicular bisector of a given
chord (cuts the chord into two equal segments and intersects
the chord at a right angle), then that line will pass through
the centre of the circle.
If you have any two of the above statements, then the third is
true.
two sides are congruent. Note: The sides
opposite the equal angle are also equal.
Equilateral
all three sides are congruent. Note: The
sides opposite the equal angle are also equal.
Click the applet once to activate:
Use the applet to create an isosceles triangle (exactly two sides
are inscribed in the same circle. Note that the angles opposite the
equal sides are also equal.
Set the number of sides to 30. Notice how close
the regular polygon is to a circle. Use the circumference formula
to calculate a close appoximation to the perimeter of the polyon.
With this hint you will likely be able to finish this question.
page 7, Q8
The opposite angles of a cyclic quadrilateral
are supplementary (total 180o). Therefore the angles
in a cyclic quadrilateral total 360o.
The sum of the interior angles in a regular polgyon
is equal to 180(n-2), where n is the number of sides of the polygon. Measure
of Each Interior Angle is equal to [180(n-2)]/n.
page 9, Q11 - Try this one on your own.
page 10, Q12 - Try this one on your own.
page 11, Q13 - Try this one on your own.
Omit Project Booklet for Module 6.
Companion CD included in coiled booklet for Module 1 includes the following
resources for this unit.
No multimedia segments available.
Module 7 - Measurement
Omit Project Booklet for Module 7.
Companion CD included in coiled booklet for Module 1 includes the following
resources for this unit.
Measuring - not available at this time
Precision: Floppy disk - not available at this time
Percentage Error - not available at this time
Machinist - not available at this time
Precision and Accuracy - not available at this time